Author Topic: Group rides: Spring 2009  (Read 50425 times)

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Offline Plantains

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Re: Group rides: Spring 2009
« Reply #100 on: June 20, 2009, 12:10:13 AM »
lol... thats cool.

interpolated is a good word.
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Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #101 on: June 22, 2009, 01:35:06 PM »
anyone up for a longer (~2hr) easy ride today at 5:30?...leaving from the union?
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Casey

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Re: Group rides: Spring 2009
« Reply #102 on: June 22, 2009, 01:50:37 PM »
i am.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #103 on: June 22, 2009, 02:12:19 PM »
yeah... I think I'm finally feeling it.
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Offline Gus Gus

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Re: Group rides: Spring 2009
« Reply #104 on: June 22, 2009, 02:44:11 PM »
I'm going to have to pass today. Unless you plan on riding by Fargo... then I'm all in.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #105 on: June 22, 2009, 04:02:29 PM »
I have well deserved day off today :-)
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #106 on: June 22, 2009, 04:52:42 PM »
"Well deserved"? That's debatable.
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Mario

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Re: Group rides: Spring 2009
« Reply #107 on: June 22, 2009, 06:42:43 PM »
You are debatable!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #108 on: June 22, 2009, 10:26:03 PM »
That's what she said!

Meh...no...that doesn't really work.
Life is complex.  It has a real part and an imaginary part.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #109 on: June 24, 2009, 08:43:01 AM »
Easy ride today, at 5 leaving from the Union. About 1.5 hours of enjoyable ride in beautiful weather. You better be there or we will come and find you!! Don't waste such a beautiful day!!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #110 on: June 26, 2009, 06:27:32 PM »
7:15 tomorrow morning 1.5 hours, if it's not raining and you're not sleeping.  Both are likely.
Life is complex.  It has a real part and an imaginary part.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #111 on: June 26, 2009, 11:55:29 PM »
As of right now it looks like it might rain.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #112 on: June 29, 2009, 10:06:15 AM »
Easy , about one hour ride today at 6 leaving from the Union.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #113 on: June 29, 2009, 02:42:59 PM »
I'll see you there, DAWG
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Mario

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Re: Group rides: Spring 2009
« Reply #114 on: July 01, 2009, 02:35:42 PM »
Time trial ,today , starting at 6:30 at Marryifeld (I have no clue how to spell it). Hope to see you there. It's beautiful weather.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #115 on: July 06, 2009, 01:49:32 PM »
Easy ride today, July 6, about one hour long, leaving form the union at 6:30. Come and enjoy bike riding.   
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #116 on: July 07, 2009, 05:13:44 PM »
7:30, a couple hours moderate/easy.
Life is complex.  It has a real part and an imaginary part.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #117 on: July 09, 2009, 11:22:57 PM »
I have a long three hours ride tomorrow, at fairly easy pace. If you want to join me , let me know here or send me personal message. I will be going sometime around 11-12.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #118 on: July 11, 2009, 09:49:10 PM »
long, easy-moderate, up to 3 hours ride, tomorrow 7/12. Leaving form the Union about 12 (pending the weather conditions ). I will give upgrade tomorrow about 11. Don't forget food and drinks with you!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #119 on: July 12, 2009, 10:58:25 AM »
Noon it is. Let's enjoy the day!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

 

anything
realistic